Sedimentation Concentration

To be held in a network, each fibre needs at least 3 contacts with other fibres; so we can solve for the minimal concentration for this to occur.

$$3=n_{contacts}=\frac{3 n_{crowd}^{sed}}{A}= 2A c_{vol}^{sed}$$ (1)

  

Figure 4: Assuming 3 contacts per fibre for minimal coherence, we obtain the mean volumetric sedimentation concentration $c^{sed}_{vol}\, \%$ as a function only of fibre aspect ratio A. This gives a crude way to estimate the effective aspect ratio of fibres.